Where is the hole for the following function located?f (x) = StartFraction x + 3 Over (x minus 4) (x + 3) EndFractionanswer choices ->x = –3y = –3x = 3y = 3
Accepted Solution
A:
At x = -3 is located a hole. Explanation:In this problem, we have the following function:[tex]f(x)=\frac{x+3}{(x-4)(x+3)}[/tex]A hole will lie at the x-values that makes the function undefined, that is, when the denominator is zero. In a mathematical language:[tex](x-4)(x+3)=0[/tex]From this equation, we get two solutions:[tex]x=4 \\ \\ x=-3[/tex]At those x-values the function will have a hole. From the choices:At x = -3 is located a hole. Learn more:Derivative: