what is the perimeter of a polygon abcd vertex a(5,12) b(9,9) c(12,5) d(0,0)a.28 unitsb.32 unitsc.36 unitsd.44 units

Answer:36Step-by-step explanation:We have to compute 4 distances and then add them up.It may help to draw this first to see which distances to compute. So I'm going to start with computing the distance from (0,0) to (5,12), then from (5,12) to (9,9), then from (9,9) to (12,5), and then finally from (12,5) to (0,0).So distance from (0,0) to (5,12)d=sqrt((5-0)^2+(12-0)^2)=sqrt(25+144)=sqrt(169)=13Distance from (5,12) to (9,9)d=sqrt((9-5)^2+(12-9)^2)=sqrt(4^2+3^2)=sqrt(16+9)=sqrt(25)=5Distance from (9,9) to (12,5)d=sqrt((12-9)^2+(9-5)^2)=sqrt(3^2+4^2)=sqrt(9+16)=sqrt(25)=5Distance from (12,5) to (0,0)d=sqrt((12-0)^2+(5-0)^2)=sqrt(12^2+5^2)=sqrt(144+25)=sqrt(169)=13.Up all of our distances 13+5+5+13=(13+13)+(5+5)=26+10=36