MATH SOLVE

2 months ago

Q:
# A magazine has 1,620,000 subscribers, of whom 640,000 are women and 980,000 are men. Thirty percent of the women read the advertisements in the magazine and 50 percent of the men read the advertisements in the magazine. A random sample of 100 subscribers is selected. What is the expected number of subscribers in the sample who read the advertisements?

Accepted Solution

A:

Answer:Expected number of subscribers in the sample who read the advertisements=42Step-by-step explanation:Step 1Determine the proportion of both men and women subscribers as shown;Proportion of Men subscribers=number of men subscribers/total number of subscriberswhere;number of men subscribers=980,000total number of subscribers=number of men+number of womentotal number of subscribers=(980,000+640,000)=1,620,000replacing;proportion of men subscribers=980,000/1,620,000=98/162Step 2Proportion of women subscribers=1-(98/162)=64/162Step 3Expected proportion of men that read the advertisement=(50/100)Γ(98/162)=4,900/16,200=49/162Expected proportion of women that read the advertisement=(30/100)Γ(64/162)=1,920/16,200=192/1620Step 4Total number of proportion=(49/162)+(192/1620)=341/810Expected number from the sample=(341/810)Γ100=42Expected number of subscribers in the sample who read the advertisements=42